0

0/19

20 Anwendungen

0/19/2

20.2 Abstände/Schnittpunkte von Geraden

0/19/2/7

20.2.5 Anwendungsbeispiele

0/19/2/7/4 .
Beispiel 20 - 208
Der Sicherheitsabstand zweier Flugzeuge sei 200m. Die Flugzeuge bewegen sich längs der Geraden:

r 1 → ( λ 1 )=( 100 200 100 )m+ λ 1 ( 100 100 100 )m MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr 4rNCHbGeaGqiVCI8FfYJH8YrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbb a9q8WqFfeaY=biLkVcLq=JHqpepeea0=as0Fb9pgeaYRXxe9vr0=vr 0=vqpWqaaeaabaGaaiaacaqaaeaadaqaaqaaaOqaaabaaaaaaaaape Waa8HaaeaacaWGYbWaaSbaaSqaaiaaigdaaeqaaaGccaGLxdcadaqa daqaaiabeU7aSnaaBaaaleaacaaIXaaabeaaaOGaayjkaiaawMcaai abg2da9maabmaabaqbaeqabmqaaaqaaiaaigdacaaIWaGaaGimaaqa aiaaikdacaaIWaGaaGimaaqaaiaaigdacaaIWaGaaGimaaaaaiaawI cacaGLPaaacaWGTbGaey4kaSIaeq4UdW2aaSbaaSqaaiaaigdaaeqa aOWaaeWaaeaafaqabeWabaaabaGaaGymaiaaicdacaaIWaaabaGaaG ymaiaaicdacaaIWaaabaGaaGymaiaaicdacaaIWaaaaaGaayjkaiaa wMcaaiaad2gaaaa@548D@            und      r 2 → ( λ 2 )=( 300 0 300 )m+ λ 2 ( 200 0 100 )m MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr 4rNCHbGeaGqiVCI8FfYJH8YrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbb a9q8WqFfeaY=biLkVcLq=JHqpepeea0=as0Fb9pgeaYRXxe9vr0=vr 0=vqpWqaaeaabaGaaiaacaqaaeaadaqaaqaaaOqaaabaaaaaaaaape Waa8HaaeaacaWGYbWaaSbaaSqaaiaaikdaaeqaaaGccaGLxdcadaqa daqaaiabeU7aSnaaBaaaleaacaaIYaaabeaaaOGaayjkaiaawMcaai abg2da9maabmaabaqbaeqabmqaaaqaaiaaiodacaaIWaGaaGimaaqa aiaaicdaaeaacaaIZaGaaGimaiaaicdaaaaacaGLOaGaayzkaaGaam yBaiabgUcaRiabeU7aSnaaBaaaleaacaaIYaaabeaakmaabmaabaqb aeqabmqaaaqaaiaaikdacaaIWaGaaGimaaqaaiaaicdaaeaacaaIXa GaaGimaiaaicdaaaaacaGLOaGaayzkaaGaamyBaaaa@51AA@ .
.
Wird der Sicherheitsabstand eingehalten? .
.
[ a 1 → a 2 → ( r 2 → − r 1 → ) ]=| 100 100 100 200 0 100 200 −200 200 |=−4⋅ 10 6 m 3 MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr 4rNCHbGeaGqiVCI8FfYJH8YrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbb a9q8WqFfeaY=biLkVcLq=JHqpepeea0=as0Fb9pgeaYRXxe9vr0=vr 0=vqpWqaaeaabaGaaiaacaqaaeaadaqaaqaaaOqaamaadmaabaWaa8 HaaeaacaWGHbWaaSbaaSqaaiaaigdaaeqaaaGccaGLxdcadaWhcaqa aiaadggadaWgaaWcbaGaaGOmaaqabaaakiaawEniamaabmaabaWaa8 HaaeaacaWGYbWaaSbaaSqaaiaaikdaaeqaaaGccaGLxdcacqGHsisl daWhcaqaaiaadkhadaWgaaWcbaGaaGymaaqabaaakiaawEniaaGaay jkaiaawMcaaaGaay5waiaaw2faaiabg2da9maaemaabaqbaeqabmWa aaqaaiaaigdacaaIWaGaaGimaaqaaiaaigdacaaIWaGaaGimaaqaai aaigdacaaIWaGaaGimaaqaaiaaikdacaaIWaGaaGimaaqaaiaaicda aeaacaaIXaGaaGimaiaaicdaaeaacaaIYaGaaGimaiaaicdaaeaacq GHsislcaaIYaGaaGimaiaaicdaaeaacaaIYaGaaGimaiaaicdaaaaa caGLhWUaayjcSdGaeyypa0JaeyOeI0IaaGinaiabgwSixlaaigdaca aIWaWaaWbaaSqabeaacaaI2aaaaOGaamyBamaaCaaaleqabaGaaG4m aaaaaaa@6944@

a 1 → × a 2 → =| x y z 100 100 100 200 0 100 | m 2 =( 10 4 10 4 −2⋅ 10 4 ) m 2 MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr 4rNCHbGeaGqiVCI8FfYJH8YrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbb a9q8WqFfeaY=biLkVcLq=JHqpepeea0=as0Fb9pgeaYRXxe9vr0=vr 0=vqpWqaaeaabaGaaiaacaqaaeaadaqaaqaaaOqaamaaFiaabaGaam yyamaaBaaaleaacaaIXaaabeaaaOGaay51GaGaey41aq7aa8Haaeaa caWGHbWaaSbaaSqaaiaaikdaaeqaaaGccaGLxdcacqGH9aqpdaabda qaauaabeqadmaaaeaacaWG4baabaGaamyEaaqaaiaadQhaaeaacaaI XaGaaGimaiaaicdaaeaacaaIXaGaaGimaiaaicdaaeaacaaIXaGaaG imaiaaicdaaeaacaaIYaGaaGimaiaaicdaaeaacaaIWaaabaGaaGym aiaaicdacaaIWaaaaaGaay5bSlaawIa7aiaad2gadaahaaWcbeqaai aaikdaaaGccqGH9aqpdaqadaqaauaabeqadeaaaeaacaaIXaGaaGim amaaCaaaleqabaGaaGinaaaaaOqaaiaaigdacaaIWaWaaWbaaSqabe aacaaI0aaaaaGcbaGaeyOeI0IaaGOmaiabgwSixlaaigdacaaIWaWa aWbaaSqabeaacaaI0aaaaaaaaOGaayjkaiaawMcaaiaad2gadaahaa Wcbeqaaiaaikdaaaaaaa@6383@

.

d = 4 ⋅ 106 6 ⋅ 104m ≈ 163m .

.

Teilen